TSTP Solution File: SEV161^5 by Duper---1.0

View Problem - Process Solution

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% File     : Duper---1.0
% Problem  : SEV161^5 : TPTP v8.1.2. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n020.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 19:24:23 EDT 2023

% Result   : Theorem 3.72s 3.91s
% Output   : Proof 3.72s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem    : SEV161^5 : TPTP v8.1.2. Released v4.0.0.
% 0.00/0.14  % Command    : duper %s
% 0.13/0.35  % Computer : n020.cluster.edu
% 0.13/0.35  % Model    : x86_64 x86_64
% 0.13/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.35  % Memory   : 8042.1875MB
% 0.13/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.35  % CPULimit   : 300
% 0.13/0.35  % WCLimit    : 300
% 0.13/0.35  % DateTime   : Thu Aug 24 02:37:16 EDT 2023
% 0.13/0.35  % CPUTime    : 
% 3.72/3.91  SZS status Theorem for theBenchmark.p
% 3.72/3.91  SZS output start Proof for theBenchmark.p
% 3.72/3.91  Clause #0 (by assumption #[]): Eq (Not (∀ (Xr : a → a → Prop) (Xx Xy : a), Iff (Xr Xx Xy) (Xr Xx Xy))) True
% 3.72/3.91  Clause #1 (by clausification #[0]): Eq (∀ (Xr : a → a → Prop) (Xx Xy : a), Iff (Xr Xx Xy) (Xr Xx Xy)) False
% 3.72/3.91  Clause #2 (by clausification #[1]): ∀ (a_1 : a → a → Prop), Eq (Not (∀ (Xx Xy : a), Iff (skS.0 0 a_1 Xx Xy) (skS.0 0 a_1 Xx Xy))) True
% 3.72/3.91  Clause #3 (by clausification #[2]): ∀ (a_1 : a → a → Prop), Eq (∀ (Xx Xy : a), Iff (skS.0 0 a_1 Xx Xy) (skS.0 0 a_1 Xx Xy)) False
% 3.72/3.91  Clause #4 (by clausification #[3]): ∀ (a_1 : a → a → Prop) (a_2 : a),
% 3.72/3.91    Eq (Not (∀ (Xy : a), Iff (skS.0 0 a_1 (skS.0 1 a_1 a_2) Xy) (skS.0 0 a_1 (skS.0 1 a_1 a_2) Xy))) True
% 3.72/3.91  Clause #5 (by clausification #[4]): ∀ (a_1 : a → a → Prop) (a_2 : a),
% 3.72/3.91    Eq (∀ (Xy : a), Iff (skS.0 0 a_1 (skS.0 1 a_1 a_2) Xy) (skS.0 0 a_1 (skS.0 1 a_1 a_2) Xy)) False
% 3.72/3.91  Clause #6 (by clausification #[5]): ∀ (a_1 : a → a → Prop) (a_2 a_3 : a),
% 3.72/3.91    Eq
% 3.72/3.91      (Not
% 3.72/3.91        (Iff (skS.0 0 a_1 (skS.0 1 a_1 a_2) (skS.0 2 a_1 a_2 a_3)) (skS.0 0 a_1 (skS.0 1 a_1 a_2) (skS.0 2 a_1 a_2 a_3))))
% 3.72/3.91      True
% 3.72/3.91  Clause #7 (by clausification #[6]): ∀ (a_1 : a → a → Prop) (a_2 a_3 : a),
% 3.72/3.91    Eq (Iff (skS.0 0 a_1 (skS.0 1 a_1 a_2) (skS.0 2 a_1 a_2 a_3)) (skS.0 0 a_1 (skS.0 1 a_1 a_2) (skS.0 2 a_1 a_2 a_3)))
% 3.72/3.91      False
% 3.72/3.91  Clause #8 (by clausification #[7]): ∀ (a_1 : a → a → Prop) (a_2 a_3 : a),
% 3.72/3.91    Or (Eq (skS.0 0 a_1 (skS.0 1 a_1 a_2) (skS.0 2 a_1 a_2 a_3)) False)
% 3.72/3.91      (Eq (skS.0 0 a_1 (skS.0 1 a_1 a_2) (skS.0 2 a_1 a_2 a_3)) False)
% 3.72/3.91  Clause #9 (by clausification #[7]): ∀ (a_1 : a → a → Prop) (a_2 a_3 : a),
% 3.72/3.91    Or (Eq (skS.0 0 a_1 (skS.0 1 a_1 a_2) (skS.0 2 a_1 a_2 a_3)) True)
% 3.72/3.91      (Eq (skS.0 0 a_1 (skS.0 1 a_1 a_2) (skS.0 2 a_1 a_2 a_3)) True)
% 3.72/3.91  Clause #10 (by eliminate duplicate literals #[8]): ∀ (a_1 : a → a → Prop) (a_2 a_3 : a), Eq (skS.0 0 a_1 (skS.0 1 a_1 a_2) (skS.0 2 a_1 a_2 a_3)) False
% 3.72/3.91  Clause #11 (by eliminate duplicate literals #[9]): ∀ (a_1 : a → a → Prop) (a_2 a_3 : a), Eq (skS.0 0 a_1 (skS.0 1 a_1 a_2) (skS.0 2 a_1 a_2 a_3)) True
% 3.72/3.91  Clause #12 (by superposition #[11, 10]): Eq True False
% 3.72/3.91  Clause #13 (by clausification #[12]): False
% 3.72/3.91  SZS output end Proof for theBenchmark.p
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